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How is preference given in operator overloading?


Asked by Collins Eaton on Dec 09, 2021 FAQ



In operator overloading preference is always given to user-defined implementations rather than predefined implementations. In overloading, overloaded methods should have a different type of arguments, different number of arguments and order of arguments should be different. So operator overloaded methods are same like any other methods.
Additionally,
C++ Overloading (Operator and Function) C++ allows you to specify more than one definition for a function name or an operator in the same scope, which is called function overloading and operator overloading respectively.
In this manner, C++ Overloading (Operator and Function) C++ allows you to specify more than one definition for a function name or an operator in the same scope, which is called function overloading and operator overloading respectively. An overloaded declaration is a declaration that is declared with the same name as a previously declared declaration in ...
Besides,
Overloading operator << and overloading operator >> are similar to overloading operator +. These are binary operators. But in overloading operator <<, the left operand is the ‘cout’ object and the right operand is the class object. The ‘cout’ is actually an object of type ostream.
In addition,
Below is the syntax of implementing operator overloading: Operator is the keyword which is used to implement operator overloading. The return type of operator overload can never be void. In operator overloading preference is always given to user-defined implementations rather than predefined implementations.